組合語言期末驗收

下星期要考試囉! 據說占總成績15%
大家記得看嘿 XD
附上 題目出處
以下答案給大家參考囉!
最後修訂 12/26/pm 5:00


1.

#include <stdio.h>

int main()
{
    char Value = 0x49;
    char H,L;
    _asm{
        MOV AX,0
        MOV AL,[Value]
        SHL AX,4
        SHR AL,4
        MOV [H],AH
        MOV [L],AL
    }
    printf("High = %#x\n",H);
    printf("Low = %#x\n",L);
    scanf("123");
    return 0;
}

2.

#include <stdio.h>

int main()
{
    short v1 = 0x7800;
    short v2 = 0x8010;
    short Max;
    _asm{
        MOV AX,[v1]
        CMP AX,[v2]
        JGE M
        MOV AX,[v2]
      M:
        MOV [Max],AX
    }
    printf("Max = %#x\n",Max);
    scanf("123");
    return 0;
}

3.

#include <stdio.h>
 
int main()
{
    short n1 = 0x9156;
    short n2 = 0x1023;
    short n3 = 0x7849;
    short Min;
    _asm{
        MOV AX,[n1]
        CMP AX,[n2]
        JG N2
        JMP N3
     N2:
        MOV AX,[n2]
     N3:
        CMP AX,[n3]
        JL END
        MOV AX,[n3]
    END:
        MOV [Min],AX
    }
    printf("Min = %#x\n",Min);
    scanf("123");
    return 0;
}

4.

#include <stdio.h>

int main()
{
   int n=3; // 資料元素的個數
   int sum = 0; // 儲存總和的位置
   int x[]={2040,-1222,242}; // 資料由此開始
    _asm{
        LEA EDI,[x]
        MOV ECX,[n]
      R:
        MOV EAX,[EDI]
        ADD [sum],EAX
        ADD EDI,4
        LOOP R
    }
    printf("Sum = %d\n",sum);
    scanf("123");
    return 0;
}

5.

#include <stdio.h>

int main()
{
   int n=3; // 資料元素之個數
   int cnt=0; // 儲存負數個數
   short x[]={0x0f1D, 0x7E0A, 0x824B}; // 資料
    _asm{
        LEA EDI,[x]
        MOV ECX,[n]
      R:
        MOV AX,[EDI]
        CMP AX,-1
        JG G
        INC [cnt]
      G:
        ADD EDI,2
        LOOP R
    }
    printf("cnt = %d\n",cnt);
    scanf("123");
    return 0;
}

6.

#include <stdio.h>

int main()
{
   short n = 4;
   short Max = 0;
   short x[]={0xA484, 0x71AC, 0xE57A, 0x32F1};
    _asm{
        LEA EDI,[x]
        MOV CX,[n]
      R:
        MOV AX,[EDI]
        CMP [Max],AX
        JG G 
        MOV [Max],AX
      G:
        ADD EDI,2
        LOOP R
    }
    printf("Max = %#x\n",Max);
    scanf("123");
    return 0;
}

7.

#include <stdio.h>
 
int main()
{
    int n = 6;
    int Pos = 0, Zer = 0, Neg = 0;
    short Start[]={0x7602, 0x8D48, 0x2120, 0, 0xE605, 4};
    _asm{
        LEA EDI,[Start]
        MOV ECX,[n]
      R:
        MOV AX,[EDI]
        CMP AX,0
        JG G
        JE E
        INC [Neg]
        JMP Next
      G:
        INC [Pos]
        JMP Next
      E:
        INC [Zer]
   Next:
        ADD EDI,2
        LOOP R
    }
    printf("Pos = %d\n",Pos);
    printf("Zer = %d\n",Zer);
    printf("Neg = %d\n",Neg);
    scanf("123");
    return 0;
}

8.

#include <stdio.h>

int main()
{
    char Start[]="Hello, this is my first program.";
    int Len = 0;
    _asm{
        LEA EDI,[Start]
      R:
        MOV AL,[EDI]
        AND [EDI],0xff
        JZ END
        INC [Len]
        ADD EDI,1
        JMP R
    END:
    }
    printf("Len = %d\n",Len);
    scanf("123");
    return 0;
}

9.

#include <stdio.h>

int main()
{
    char Start[]="Hello 101+-*/, this is my first PROGRAM.";
    int c = 0;
    _asm{
        LEA EDI,[Start]
      R:
        CMP [EDI],0
        JZ END
        CMP [EDI],65
        JNGE E
        CMP [EDI],97
        JNL E
        ADD [EDI],32
      E:
        ADD EDI,1
        JMP R
    END:
    }
    printf("%s\n",Start);
    scanf("123");
    return 0;
}

10.

#include <stdio.h>
 
int main()
{
    char number = 0x5a;
    char Start[8];
    _asm{
        LEA EDI,[Start]
        MOV AL,[number]
        MOV ECX,8
      R:
        SAR AL,1
        JC ONE
        MOV [EDI],0x30
        JMP C
    ONE:
        MOV [EDI],0x31
      C:
        ADD EDI,1
        LOOP R
    END:
    }
    for(int i=0;i<8;i++)
      printf("Start[%d] = %#x\n",i,Start[i]);
    scanf("123");
    return 0;
}